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Momentum Maps and Noether’s Theorem

How symmetries generate conserved quantities on symplectic manifolds, and why Lie group actions provide the right framework.

Noether’s theorem is often stated as “continuous symmetries correspond to conserved quantities.” Symplectic geometry makes this statement precise: a momentum map connects the infinitesimal generators of a symmetry group to Hamiltonian functions.

1. Lie Group Actions

Let a Lie group GG act on a symplectic manifold (M,ω)(M, \omega). An element ξ∈g\xi \in \mathfrak{g} of its Lie algebra induces the fundamental vector field

ξM(x)=ddt∣t=0exp⁡(tξ)⋅x. \xi_M(x) = \left.\frac{\mathrm{d}}{\mathrm{d}t}\right|_{t = 0} \exp(t\xi) \cdot x .

If the group action preserves the symplectic form, then LξMω=0\mathcal{L}_{\xi_M}\omega = 0. Locally, ιξMω\iota_{\xi_M}\omega is therefore a closed one-form.

2. Momentum Maps

A momentum map is a map J:M→g∗J: M \to \mathfrak{g}^* such that, for every ξ∈g\xi \in \mathfrak{g}, the function

Jξ(x)=⟨J(x),ξ⟩ J_\xi(x) = \langle J(x), \xi \rangle

has ξM\xi_M as its Hamiltonian vector field. In other words,

ιξMω=dJξ. \iota_{\xi_M}\omega = \mathrm{d}J_\xi .
Proof

The GG-invariance of HH gives ξM[H]=0\xi_M[H] = 0. On the other hand,

ddtJξ={Jξ,H}=ω(ξM,XH)=dH(ξM)=0. \frac{\mathrm{d}}{\mathrm{d}t}J_\xi = \{J_\xi, H\} = \omega(\xi_M, X_H) = \mathrm{d}H(\xi_M) = 0 .□

3. Rotational Symmetry

The rotation group SO(3)\mathrm{SO}(3) in three dimensions acts on a particle’s phase space, and its momentum map is the angular momentum

J(q,p)=q×p. J(q, p) = q \times p .

A central potential depends only on ∣q∣|q|, so it is rotationally invariant and angular momentum is conserved. The familiar vector formula is thus a concrete coordinate expression of a general geometric mechanism.